Integrand size = 21, antiderivative size = 156 \[ \int \frac {\cos (e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=-\frac {3 b \left (4 (a+b)^2+(2 a+b)^2\right ) \text {arctanh}\left (\frac {\sqrt {a} \sin (e+f x)}{\sqrt {a+b}}\right )}{8 a^{7/2} (a+b)^{5/2} f}+\frac {\sin (e+f x)}{a^3 f}-\frac {b^3 \sin (e+f x)}{4 a^3 (a+b) f \left (a+b-a \sin ^2(e+f x)\right )^2}+\frac {3 b^2 (4 a+3 b) \sin (e+f x)}{8 a^3 (a+b)^2 f \left (a+b-a \sin ^2(e+f x)\right )} \]
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Time = 0.25 (sec) , antiderivative size = 156, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {4232, 398, 1171, 393, 214} \[ \int \frac {\cos (e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=-\frac {3 b \left (4 (a+b)^2+(2 a+b)^2\right ) \text {arctanh}\left (\frac {\sqrt {a} \sin (e+f x)}{\sqrt {a+b}}\right )}{8 a^{7/2} f (a+b)^{5/2}}-\frac {b^3 \sin (e+f x)}{4 a^3 f (a+b) \left (-a \sin ^2(e+f x)+a+b\right )^2}+\frac {3 b^2 (4 a+3 b) \sin (e+f x)}{8 a^3 f (a+b)^2 \left (-a \sin ^2(e+f x)+a+b\right )}+\frac {\sin (e+f x)}{a^3 f} \]
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Rule 214
Rule 393
Rule 398
Rule 1171
Rule 4232
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {\left (1-x^2\right )^3}{\left (a+b-a x^2\right )^3} \, dx,x,\sin (e+f x)\right )}{f} \\ & = \frac {\text {Subst}\left (\int \left (\frac {1}{a^3}-\frac {b \left (3 a^2+3 a b+b^2\right )-3 a b (2 a+b) x^2+3 a^2 b x^4}{a^3 \left (a+b-a x^2\right )^3}\right ) \, dx,x,\sin (e+f x)\right )}{f} \\ & = \frac {\sin (e+f x)}{a^3 f}-\frac {\text {Subst}\left (\int \frac {b \left (3 a^2+3 a b+b^2\right )-3 a b (2 a+b) x^2+3 a^2 b x^4}{\left (a+b-a x^2\right )^3} \, dx,x,\sin (e+f x)\right )}{a^3 f} \\ & = \frac {\sin (e+f x)}{a^3 f}-\frac {b^3 \sin (e+f x)}{4 a^3 (a+b) f \left (a+b-a \sin ^2(e+f x)\right )^2}+\frac {\text {Subst}\left (\int \frac {-3 b (2 a+b)^2+12 a b (a+b) x^2}{\left (a+b-a x^2\right )^2} \, dx,x,\sin (e+f x)\right )}{4 a^3 (a+b) f} \\ & = \frac {\sin (e+f x)}{a^3 f}-\frac {b^3 \sin (e+f x)}{4 a^3 (a+b) f \left (a+b-a \sin ^2(e+f x)\right )^2}+\frac {3 b^2 (4 a+3 b) \sin (e+f x)}{8 a^3 (a+b)^2 f \left (a+b-a \sin ^2(e+f x)\right )}-\frac {\left (3 b \left (4 (a+b)^2+(2 a+b)^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+b-a x^2} \, dx,x,\sin (e+f x)\right )}{8 a^3 (a+b)^2 f} \\ & = -\frac {3 b \left (4 (a+b)^2+(2 a+b)^2\right ) \text {arctanh}\left (\frac {\sqrt {a} \sin (e+f x)}{\sqrt {a+b}}\right )}{8 a^{7/2} (a+b)^{5/2} f}+\frac {\sin (e+f x)}{a^3 f}-\frac {b^3 \sin (e+f x)}{4 a^3 (a+b) f \left (a+b-a \sin ^2(e+f x)\right )^2}+\frac {3 b^2 (4 a+3 b) \sin (e+f x)}{8 a^3 (a+b)^2 f \left (a+b-a \sin ^2(e+f x)\right )} \\ \end{align*}
Time = 1.36 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.13 \[ \int \frac {\cos (e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {-\frac {3 b \left (8 a^2+12 a b+5 b^2\right ) \text {arctanh}\left (\frac {\sqrt {a} \sin (e+f x)}{\sqrt {a+b}}\right )}{(a+b)^{5/2}}+\frac {4 \sqrt {a} \sin (e+f x) \left (8 a^4+32 a^3 b+60 a^2 b^2+51 a b^3+15 b^4-a \left (16 a^3+48 a^2 b+60 a b^2+25 b^3\right ) \sin ^2(e+f x)+8 a^2 (a+b)^2 \sin ^4(e+f x)\right )}{(a+b)^2 (a+2 b+a \cos (2 (e+f x)))^2}}{8 a^{7/2} f} \]
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Time = 3.14 (sec) , antiderivative size = 149, normalized size of antiderivative = 0.96
method | result | size |
derivativedivides | \(\frac {\frac {\sin \left (f x +e \right )}{a^{3}}+\frac {b \left (\frac {-\frac {3 a b \left (4 a +3 b \right ) \sin \left (f x +e \right )^{3}}{8 \left (a^{2}+2 a b +b^{2}\right )}+\frac {\left (12 a +7 b \right ) b \sin \left (f x +e \right )}{8 a +8 b}}{\left (a \sin \left (f x +e \right )^{2}-a -b \right )^{2}}-\frac {3 \left (8 a^{2}+12 a b +5 b^{2}\right ) \operatorname {arctanh}\left (\frac {a \sin \left (f x +e \right )}{\sqrt {a \left (a +b \right )}}\right )}{8 \left (a^{2}+2 a b +b^{2}\right ) \sqrt {a \left (a +b \right )}}\right )}{a^{3}}}{f}\) | \(149\) |
default | \(\frac {\frac {\sin \left (f x +e \right )}{a^{3}}+\frac {b \left (\frac {-\frac {3 a b \left (4 a +3 b \right ) \sin \left (f x +e \right )^{3}}{8 \left (a^{2}+2 a b +b^{2}\right )}+\frac {\left (12 a +7 b \right ) b \sin \left (f x +e \right )}{8 a +8 b}}{\left (a \sin \left (f x +e \right )^{2}-a -b \right )^{2}}-\frac {3 \left (8 a^{2}+12 a b +5 b^{2}\right ) \operatorname {arctanh}\left (\frac {a \sin \left (f x +e \right )}{\sqrt {a \left (a +b \right )}}\right )}{8 \left (a^{2}+2 a b +b^{2}\right ) \sqrt {a \left (a +b \right )}}\right )}{a^{3}}}{f}\) | \(149\) |
risch | \(-\frac {i {\mathrm e}^{i \left (f x +e \right )}}{2 a^{3} f}+\frac {i {\mathrm e}^{-i \left (f x +e \right )}}{2 a^{3} f}-\frac {i b^{2} \left (12 a^{2} {\mathrm e}^{7 i \left (f x +e \right )}+9 a b \,{\mathrm e}^{7 i \left (f x +e \right )}+12 a^{2} {\mathrm e}^{5 i \left (f x +e \right )}+49 a b \,{\mathrm e}^{5 i \left (f x +e \right )}+28 b^{2} {\mathrm e}^{5 i \left (f x +e \right )}-12 a^{2} {\mathrm e}^{3 i \left (f x +e \right )}-49 a b \,{\mathrm e}^{3 i \left (f x +e \right )}-28 b^{2} {\mathrm e}^{3 i \left (f x +e \right )}-12 a^{2} {\mathrm e}^{i \left (f x +e \right )}-9 a b \,{\mathrm e}^{i \left (f x +e \right )}\right )}{4 a^{3} \left (a +b \right )^{2} f \left (a \,{\mathrm e}^{4 i \left (f x +e \right )}+2 a \,{\mathrm e}^{2 i \left (f x +e \right )}+4 b \,{\mathrm e}^{2 i \left (f x +e \right )}+a \right )^{2}}+\frac {3 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \left (a +b \right ) {\mathrm e}^{i \left (f x +e \right )}}{\sqrt {a^{2}+a b}}-1\right ) b}{2 \sqrt {a^{2}+a b}\, \left (a +b \right )^{2} f a}+\frac {9 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \left (a +b \right ) {\mathrm e}^{i \left (f x +e \right )}}{\sqrt {a^{2}+a b}}-1\right ) b^{2}}{4 \sqrt {a^{2}+a b}\, \left (a +b \right )^{2} f \,a^{2}}+\frac {15 b^{3} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \left (a +b \right ) {\mathrm e}^{i \left (f x +e \right )}}{\sqrt {a^{2}+a b}}-1\right )}{16 \sqrt {a^{2}+a b}\, \left (a +b \right )^{2} f \,a^{3}}-\frac {3 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \left (a +b \right ) {\mathrm e}^{i \left (f x +e \right )}}{\sqrt {a^{2}+a b}}-1\right ) b}{2 \sqrt {a^{2}+a b}\, \left (a +b \right )^{2} f a}-\frac {9 \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \left (a +b \right ) {\mathrm e}^{i \left (f x +e \right )}}{\sqrt {a^{2}+a b}}-1\right ) b^{2}}{4 \sqrt {a^{2}+a b}\, \left (a +b \right )^{2} f \,a^{2}}-\frac {15 b^{3} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \left (a +b \right ) {\mathrm e}^{i \left (f x +e \right )}}{\sqrt {a^{2}+a b}}-1\right )}{16 \sqrt {a^{2}+a b}\, \left (a +b \right )^{2} f \,a^{3}}\) | \(593\) |
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Leaf count of result is larger than twice the leaf count of optimal. 351 vs. \(2 (148) = 296\).
Time = 0.33 (sec) , antiderivative size = 727, normalized size of antiderivative = 4.66 \[ \int \frac {\cos (e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\left [\frac {3 \, {\left (8 \, a^{2} b^{3} + 12 \, a b^{4} + 5 \, b^{5} + {\left (8 \, a^{4} b + 12 \, a^{3} b^{2} + 5 \, a^{2} b^{3}\right )} \cos \left (f x + e\right )^{4} + 2 \, {\left (8 \, a^{3} b^{2} + 12 \, a^{2} b^{3} + 5 \, a b^{4}\right )} \cos \left (f x + e\right )^{2}\right )} \sqrt {a^{2} + a b} \log \left (-\frac {a \cos \left (f x + e\right )^{2} + 2 \, \sqrt {a^{2} + a b} \sin \left (f x + e\right ) - 2 \, a - b}{a \cos \left (f x + e\right )^{2} + b}\right ) + 2 \, {\left (8 \, a^{4} b^{2} + 34 \, a^{3} b^{3} + 41 \, a^{2} b^{4} + 15 \, a b^{5} + 8 \, {\left (a^{6} + 3 \, a^{5} b + 3 \, a^{4} b^{2} + a^{3} b^{3}\right )} \cos \left (f x + e\right )^{4} + {\left (16 \, a^{5} b + 60 \, a^{4} b^{2} + 69 \, a^{3} b^{3} + 25 \, a^{2} b^{4}\right )} \cos \left (f x + e\right )^{2}\right )} \sin \left (f x + e\right )}{16 \, {\left ({\left (a^{9} + 3 \, a^{8} b + 3 \, a^{7} b^{2} + a^{6} b^{3}\right )} f \cos \left (f x + e\right )^{4} + 2 \, {\left (a^{8} b + 3 \, a^{7} b^{2} + 3 \, a^{6} b^{3} + a^{5} b^{4}\right )} f \cos \left (f x + e\right )^{2} + {\left (a^{7} b^{2} + 3 \, a^{6} b^{3} + 3 \, a^{5} b^{4} + a^{4} b^{5}\right )} f\right )}}, \frac {3 \, {\left (8 \, a^{2} b^{3} + 12 \, a b^{4} + 5 \, b^{5} + {\left (8 \, a^{4} b + 12 \, a^{3} b^{2} + 5 \, a^{2} b^{3}\right )} \cos \left (f x + e\right )^{4} + 2 \, {\left (8 \, a^{3} b^{2} + 12 \, a^{2} b^{3} + 5 \, a b^{4}\right )} \cos \left (f x + e\right )^{2}\right )} \sqrt {-a^{2} - a b} \arctan \left (\frac {\sqrt {-a^{2} - a b} \sin \left (f x + e\right )}{a + b}\right ) + {\left (8 \, a^{4} b^{2} + 34 \, a^{3} b^{3} + 41 \, a^{2} b^{4} + 15 \, a b^{5} + 8 \, {\left (a^{6} + 3 \, a^{5} b + 3 \, a^{4} b^{2} + a^{3} b^{3}\right )} \cos \left (f x + e\right )^{4} + {\left (16 \, a^{5} b + 60 \, a^{4} b^{2} + 69 \, a^{3} b^{3} + 25 \, a^{2} b^{4}\right )} \cos \left (f x + e\right )^{2}\right )} \sin \left (f x + e\right )}{8 \, {\left ({\left (a^{9} + 3 \, a^{8} b + 3 \, a^{7} b^{2} + a^{6} b^{3}\right )} f \cos \left (f x + e\right )^{4} + 2 \, {\left (a^{8} b + 3 \, a^{7} b^{2} + 3 \, a^{6} b^{3} + a^{5} b^{4}\right )} f \cos \left (f x + e\right )^{2} + {\left (a^{7} b^{2} + 3 \, a^{6} b^{3} + 3 \, a^{5} b^{4} + a^{4} b^{5}\right )} f\right )}}\right ] \]
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Timed out. \[ \int \frac {\cos (e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\text {Timed out} \]
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Time = 0.27 (sec) , antiderivative size = 253, normalized size of antiderivative = 1.62 \[ \int \frac {\cos (e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {\frac {3 \, {\left (8 \, a^{2} b + 12 \, a b^{2} + 5 \, b^{3}\right )} \log \left (\frac {a \sin \left (f x + e\right ) - \sqrt {{\left (a + b\right )} a}}{a \sin \left (f x + e\right ) + \sqrt {{\left (a + b\right )} a}}\right )}{{\left (a^{5} + 2 \, a^{4} b + a^{3} b^{2}\right )} \sqrt {{\left (a + b\right )} a}} - \frac {2 \, {\left (3 \, {\left (4 \, a^{2} b^{2} + 3 \, a b^{3}\right )} \sin \left (f x + e\right )^{3} - {\left (12 \, a^{2} b^{2} + 19 \, a b^{3} + 7 \, b^{4}\right )} \sin \left (f x + e\right )\right )}}{a^{7} + 4 \, a^{6} b + 6 \, a^{5} b^{2} + 4 \, a^{4} b^{3} + a^{3} b^{4} + {\left (a^{7} + 2 \, a^{6} b + a^{5} b^{2}\right )} \sin \left (f x + e\right )^{4} - 2 \, {\left (a^{7} + 3 \, a^{6} b + 3 \, a^{5} b^{2} + a^{4} b^{3}\right )} \sin \left (f x + e\right )^{2}} + \frac {16 \, \sin \left (f x + e\right )}{a^{3}}}{16 \, f} \]
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Time = 0.34 (sec) , antiderivative size = 197, normalized size of antiderivative = 1.26 \[ \int \frac {\cos (e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {\frac {3 \, {\left (8 \, a^{2} b + 12 \, a b^{2} + 5 \, b^{3}\right )} \arctan \left (\frac {a \sin \left (f x + e\right )}{\sqrt {-a^{2} - a b}}\right )}{{\left (a^{5} + 2 \, a^{4} b + a^{3} b^{2}\right )} \sqrt {-a^{2} - a b}} - \frac {12 \, a^{2} b^{2} \sin \left (f x + e\right )^{3} + 9 \, a b^{3} \sin \left (f x + e\right )^{3} - 12 \, a^{2} b^{2} \sin \left (f x + e\right ) - 19 \, a b^{3} \sin \left (f x + e\right ) - 7 \, b^{4} \sin \left (f x + e\right )}{{\left (a^{5} + 2 \, a^{4} b + a^{3} b^{2}\right )} {\left (a \sin \left (f x + e\right )^{2} - a - b\right )}^{2}} + \frac {8 \, \sin \left (f x + e\right )}{a^{3}}}{8 \, f} \]
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Time = 19.72 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.12 \[ \int \frac {\cos (e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {\sin \left (e+f\,x\right )}{a^3\,f}+\frac {\frac {\sin \left (e+f\,x\right )\,\left (7\,b^3+12\,a\,b^2\right )}{8\,\left (a+b\right )}-\frac {3\,{\sin \left (e+f\,x\right )}^3\,\left (4\,a^2\,b^2+3\,a\,b^3\right )}{8\,{\left (a+b\right )}^2}}{f\,\left (2\,a^4\,b-{\sin \left (e+f\,x\right )}^2\,\left (2\,a^5+2\,b\,a^4\right )+a^5+a^3\,b^2+a^5\,{\sin \left (e+f\,x\right )}^4\right )}-\frac {3\,b\,\mathrm {atanh}\left (\frac {\sqrt {a}\,\sin \left (e+f\,x\right )}{\sqrt {a+b}}\right )\,\left (8\,a^2+12\,a\,b+5\,b^2\right )}{8\,a^{7/2}\,f\,{\left (a+b\right )}^{5/2}} \]
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